7/25/2019 Tehnici de Comp

1/5

tema 1

pr 1

%{static int nr=0;

%}

%%

(0|1)*01 {printf("cuvant acceptat: %s\n",yytext); nr++;}

[ \t\n]+ ;

. ;

\n ;

%%

void main(){

yylex();

printf("nr de cuv acceptate: %d\n",nr);

}

pr 2

%{

static int nr=0;

%}

%%

1*01* {printf("cuvant acceptat: %s\n",yytext); nr++;}

[ \t\n]+ ;

. ;

\n ;

%%

void main()

{

yylex();

printf("nr de cuv acceptate: %d\n",nr);

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}

pr 3

%{

static int nr=0;

%}

%%

(11)* {printf("cuvant acceptat: %s\n",yytext); nr++;}

[ \t\n]+ ;

. ;

\n ;%%

void main()

{

yylex();

printf("nr de cuv acceptate: %d\n",nr);

}

pr 4

%{

static int nr=0;

%}

%%

0*(10|01|11)*0* {printf("cuvant acceptat: %s\n",yytext); nr++;}

[ \t\n]+ ;

. ;

\n ;

%%

void main()

{

yylex();

printf("nr de cuv acceptate: %d\n",nr);

}

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pr 5

%{static int nr=0;

%}

%%

(0|1)*01(0|1)* {printf("%s este un cuvant care contine substringul 01. \n",yytext);}

[ \t\n]+ ;

. ;

\n ;

%%

void main(){

yylex();

printf("nr de cuv acceptate: %d\n",nr);

}

pr 6

%{static int nr=0;

%}

%%

1*0* {printf("cuvant acceptat: %s\n",yytext); nr++;}

[ \t\n]+ ;

. ;

\n ;

%%

void main()

{

yylex();

printf("nr de cuv acceptate: %d\n",nr);

}

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sau

%{

static int nr=0;%}

%%

(0|1)*01(0|1)* ;

[ \t\n]+ {printf("%s este un cuvant care contine substringul 01. \n",yytext);}

. ;

\n ;

%%

void main()

{yylex();

printf("nr de cuv acceptate: %d\n",nr);

}

tema 2

pr 1

%{

static FILE *f;

%}

%%[ \t]+ fprintf(f," ");

[\n]+ fprintf(f,"\n");

[\b\t\n] fprintf(f,yytext);

%%

void main()

{

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f=fopen("FISIER OUT CALE","w");

yylex();

fclose(f);

}

pr 2

%{

static FILE *f;

%}

%%[0-9]+ fprintf(f,"numar intreg \n");

[0-9]+(\.[0-9]+)? fprintf(f,"numar real \n");

[a-zA-Z][a-zA-Z0-9]* fprintf(f,"identificator \n");

%%

void main()

{

f=fopen("FISIER OUT CALE","w");

yylex();

fclose(f);}