Regresii rezolvate ca Functii Lineare .pdf

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    Functia de gradul 1, de 1 variabila, notata f(x,a,b). Deducerea regresiei, Matriceal 1( )

    1( ) f x a b( ) a b x Regresia care trebuie determinata

    2( ) x 1 2 3 4 5 6 7 8 9 10( ) Valorile masurate ale variabilei independente, x

    3( ) y 2.1 3.6 4.5 4 .9 5.4 5 .9 6.6 7 .9 8.1 9.5( ) Valorile masurate ale variabilei dependente, y

    4( ) Expunere teorie generala : Intre (4) - (9). Se formeaza matricea X, astfel :

    5( ) A a b( ) a b( ) AT

    vectorul necunoscutelor=

    6( ) X A y= Ecuatia Matriceala echivalenta cu ecuatia (1)

    7( ) XT

    X A XTyT=

    X

    1

    1

    1

    1

    1

    1

    1

    1

    1

    1

    1

    2

    3

    4

    5

    6

    7

    8

    9

    10

    X

    0 1

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    1 1

    1 2

    1 3

    1 4

    1 5

    1 6

    1 7

    1 8

    1 9

    1 10

    8( ) XT

    X 1

    XT

    X A XTX 1

    XTy

    T=

    9( ) A XT

    X 1

    XTy

    T=

    Calculez XT

    X 1 XTyT 1.8270.732

    10( ) f x( ) 1.827 0.732 x 11( ) E f xT yT Apoi calculez f xT yT E E Erori= m

    0

    9

    i

    f xT i yT i

    10

    m 3 10 3

    0 1 2 3 4 5 6 7 8 9 10

    2

    4

    6

    8

    10

    2

    4

    6

    8

    10

    Grafic Erori

    f xT

    i yT

    i

    i i

    f xT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    2.559

    3.291

    4.023

    4.755

    5.487

    6.219

    6.951

    7.683

    8.415

    9.147

    yT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    2.1

    3.6

    4.5

    4.9

    5.4

    5.9

    6.6

    7.9

    8.1

    9.5

    E0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    0.459

    -0.309

    -0.477

    -0.145

    0.087

    0.319

    0.351

    -0.217

    0.315

    -0.353

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    2( )Functie (regresie) Multilineara determinata prin Calcul Matriceal

    f x y z u a b c d e( ) a b x c y d z e u

    x 1.11 1.25 1.49 1.61 1.82 2.05 2.27 2.44 2.61 2.89( ) ||

    ||

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    Valori Masurate. x,y,z,u,V, unde V = vectorul variabilei dependente

    y 1.25 1.39 1.85 1.93 2.35 2.72 3.08 3.74 3.93 4.26( )A a b c d e( ) a b c d e( )

    z 2.36 2.64 2.87 2.99 3.65 4.44 4.86 5.69 5.88 6.33( )

    u 1.51 1.96 2.31 2.45 2.84 3.14 3.59 4.75 5.02 5.66( ) A a b c d e( )T

    a

    b

    c

    d

    e

    Vectorul necunoscutelor

    V 14.2 15.5 18.4 20.4 22.3 22.9 26.7 35.2 44.4 53.9( )

    Se formeaza Matricea Xq [10, 5], astfel :

    |

    |

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    |

    |

    |

    |

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    |

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    ||

    |

    |

    |

    Xq AT

    VT

    =

    XqT

    Xq AT XqT VT=

    XqT

    Xq 1

    XqT

    Xq AT XqTXq 1

    XqT

    VT

    =

    Xq

    1

    1

    1

    1

    1

    1

    1

    1

    1

    1

    1.11

    1.25

    1.49

    1.61

    1.82

    2.05

    2.27

    2.44

    2.61

    2.89

    1.25

    1.39

    1.85

    1.93

    2.35

    2.72

    3.08

    3.74

    3.93

    4.26

    2.36

    2.64

    2.87

    2.99

    3.65

    4.44

    4.86

    5.69

    5.88

    6.33

    1.51

    1.96

    2.31

    2.45

    2.84

    3.14

    3.59

    4.75

    5.02

    5.66

    Prelucrarea ecuatiei MatricealeA

    TXq

    TXq

    1Xq

    T V

    T=

    XqT

    Xq 1

    XqT

    VT

    6.594

    13.99519.901

    2.283

    20.733

    Fq x y z u( ) 6.594 13.995 x 19.901 y 2.283 z 20.773 u E Fq xT

    yT

    zT

    uT

    VT E Erori=

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    3( )

    Se1

    100

    9

    i

    Ei

    Se 0.131

    VT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    14.2

    15.5

    18.4

    20.4

    22.3

    22.9

    26.7

    35.2

    44.4

    53.9

    Fq xT

    yT

    zT

    uT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    10.044

    17.925

    18.875

    21.597

    22.772

    23.056

    27.359

    38.806

    42.578

    52.197

    E

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    -4.156

    2.425

    0.475

    1.197

    0.472

    0.156

    0.659

    3.606

    -1.822

    -1.703

    1

    100

    9

    i

    Fq xT

    yT

    zT

    uT

    i VT i

    0.131

    1 0 1 2 3 4 5 6 7 8 9 100

    510

    15

    20

    2530

    35

    40

    45

    50

    55

    60

    0

    510

    15

    20

    2530

    35

    40

    45

    50

    55

    60

    Fq xT

    yT

    zT

    uT

    i VT

    i

    i i

    Regresie Sinusoidala rezolvata Matriceal ca Regresie Lineara

    f x a b( ) a b sin x( )

    y 1.1 1.2 1.3 1.5 1.3 1.0 0.7 0.6 0.4 0.1( )

    x 1 1.1 1.3 1.6 1.9 2.1 2.3 2.5 2.8 3.1( ) U 1 1 1 1 1 1 1 1 1 1( )

    XS0 UT XS 1 sin xT A a b( )

    a

    b

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    4( )XS

    0 1

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    1 0.841

    1 0.891

    1 0.964

    1 1

    1 0.946

    1 0.863

    1 0.746

    1 0.598

    1 0.335

    1 0.042

    sin xT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    0.841

    0.891

    0.964

    1

    0.946

    0.863

    0.746

    0.598

    0.335

    0.042

    XS A yT

    = XST

    XS A XST

    yT

    = XST

    XS 1

    XST

    XS A XSTXS 1

    XST

    yT

    = A XST

    XS 1

    XST

    yT

    =

    XST

    XS 1

    XST

    yT

    0.078

    1.381

    fs z( ) 0.07825 1.38146 z z sin x

    T

    z

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    0.841

    0.891

    0.964

    1

    0.946

    0.863

    0.746

    0.598

    0.335

    0.042

    fs z( )

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    1.084

    1.153

    1.253

    1.303

    1.229

    1.114

    0.952

    0.749

    0.385

    -0.021

    yT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    1.1

    1.2

    1.3

    1.5

    1.3

    1

    0.7

    0.6

    0.4

    0.1

    yT fs z( )

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    0.016

    0.047

    0.047

    0.197

    0.071

    -0.114

    -0.252

    -0.149

    0.015

    0.121

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    i 0 9 5( )

    1 0 1 2 3 4 5 6 7 8 9 10 110.2

    0

    0.2

    0.4

    0.6

    0.8

    1

    1.2

    1.4

    1.6

    0.2

    0

    0.2

    0.4

    0.6

    0.8

    1

    1.2

    1.4

    1.6

    Grafic Erori

    fs z( )i y

    T i

    i i

    Se1

    100

    9

    i

    yT

    i fs z( ) i

    Se 2.08 10 6

    stdev yT

    fs z( ) 0.127 Stdev yT fs z( ) 0.134

    Formula stdev stdev Vi 1

    n0

    n 1

    i

    Vi mean Vi 2

    1

    2

    =

    Formula Stdev Stdev Vi 1

    n 1( )0

    n 1

    i

    Vi mean Vi 2

    =

    1

    10

    0

    9

    i

    yT

    i fs z( )( )

    i 0.00119

    2

    1

    2

    0.127

    1

    90

    9

    i

    yT

    i fs z( ) i 0.00119

    2

    1

    2

    0.134

    Regresie Logaritmica rezolvata Matriceal ca Regresie Lineara

    f x a b( ) a b log x( )y 0.01 0.02 0.13 0.25 0.31 0.36 0.37 0.41 0.49 0.51( )

    x 1 1.1 1.3 1.6 1.9 2.1 2.3 2.5 2.8 3.1( ) U 1 1 1 1 1 1 1 1 1 1( )

    XL0 UT XL1 log xT A a b( )

    a

    b

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    6( )

    log xT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    0

    0.041

    0.114

    0.204

    0.279

    0.322

    0.362

    0.398

    0.447

    0.491

    XL

    0 1

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    1 0

    1 0.041

    1 0.114

    1 0.204

    1 0.279

    1 0.322

    1 0.362

    1 0.398

    1 0.447

    1 0.491

    XL A yT

    = XLT

    XL A XLT

    yT

    = XLT

    XL 1

    XLT

    XL A XLTXL 1

    XLT

    yT

    = A XLT

    XL 1

    XLT

    yT

    = XLT

    XL 1

    XLT

    yT

    6.158 10

    3

    1.053

    fo z( ) 0.00616 1.05259 z z log xT z

    0

    0

    1

    2

    3

    4

    5

    6

    78

    9

    0

    0.041

    0.114

    0.204

    0.279

    0.322

    0.362

    0.3980.447

    0.491

    fo z( )

    0

    0

    1

    2

    3

    4

    5

    6

    78

    9

    -36.1610

    0.05

    0.126

    0.221

    0.3

    0.345

    0.387

    0.4250.477

    0.523

    yT

    0

    0

    1

    2

    3

    4

    5

    6

    78

    9

    0.01

    0.02

    0.13

    0.25

    0.31

    0.36

    0.37

    0.410.49

    0.51

    yT

    fo z( )

    0

    0

    1

    2

    3

    4

    5

    6

    78

    9

    -33.8410

    -0.03

    -33.90410

    0.029

    0.01

    0.015

    -0.017

    -0.0150.013

    -0.013

    Se1

    100

    9

    i

    yT

    i fo z( ) i

    Se 3.313 10 6

    stdev yT

    fo z( ) 0.017 Stdev yT fo z( ) 0.018 i 0 9

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    1 0 1 2 3 4 5 6 7 8 9 10 110.2

    0.1

    0

    0.1

    0.2

    0.3

    0.4

    0.5

    0.6

    0.2

    0.1

    0

    0.1

    0.2

    0.3

    0.4

    0.5

    0.6

    Grafic Erori

    fo z( )i y

    T i

    i i

    7( )

    stdev Vi 1

    n0

    n 1

    i

    Vi mean Vi 2

    1

    2

    =

    Stdev Vi 1

    n 1( ) 0

    n 1

    i

    Vi mean Vi 2

    =

    1

    100

    9

    i

    yT

    i fo z( ) i 0.00119

    2

    1

    2

    0.017

    1

    9

    0

    9

    i

    yT

    i fo z( ) i 0.00119

    2

    1

    2

    0.018

    Regresie Exponentiala cu baza [e], rezolvata ca Regresie Lineara

    f x a b( ) a b ex

    y 3.1 3.2 3.9 4.5 7.8 12.1 19.1 35.5 46.7 58.8( )

    x 1 1.1 1.3 1.6 1.9 2.4 2.9 3.5 3.8 4.1( ) U 1 1 1 1 1 1 1 1 1 1( ) yT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    3.1

    3.2

    3.9

    4.5

    7.8

    12.1

    19.1

    35.5

    46.7

    58.8

    XE0 UT XE1 ex

    T

    A a b( )a

    b

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    8( )

    ex

    T

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    2.718

    3.004

    3.669

    4.953

    6.686

    11.023

    18.174

    33.115

    44.701

    60.34

    XE

    0 1

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    1 2.718

    1 3.004

    1 3.669

    1 4.953

    1 6.686

    1 11.023

    1 18.174

    1 33.115

    1 44.701

    1 60.34

    XE A yT

    = XET

    XE A XET

    yT

    = XET

    XE 1

    XET

    XE A XETXE 1

    XET

    yT

    = A XET

    XE 1

    XET

    yT

    = XET

    XE 1

    XET

    yT

    0.668

    0.998

    fe z( ) 0.668 0.998 z z ex

    T z

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    2.718

    3.004

    3.669

    4.953

    6.686

    11.023

    18.174

    33.115

    44.701

    60.34

    fe z( )

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    3.381

    3.666

    4.33

    5.611

    7.341

    11.669

    18.806

    33.717

    45.28

    60.888

    yT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    3.1

    3.2

    3.9

    4.5

    7.8

    12.1

    19.1

    35.5

    46.7

    58.8

    yT

    fe z( )

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    -0.281

    -0.466

    -0.43

    -1.111

    0.459

    0.431

    0.294

    1.783

    1.42

    -2.088

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    9( )Se

    1

    100

    9

    i

    yT

    i fe z( ) i

    Se 1.185 10 3

    stdev yT

    fe z( ) 1.084 Stdev yT fe z( ) 1.143 i 0 9

    1 0 1 2 3 4 5 6 7 8 9 10 110

    10

    20

    30

    40

    50

    60

    70

    0

    10

    20

    30

    40

    50

    60

    70

    fe z( )i y

    T i

    i i

    stdev Vi 1

    n0

    n 1

    i

    Vi mean Vi 2

    1

    2

    =

    Stdev Vi 1

    n 1( )0

    n 1

    i

    Vi mean Vi 2

    =

    1

    100

    9

    i

    yT

    i fe z( ) i 0.001192

    1

    2

    1.084

    1

    90

    9

    i

    yT

    i fe z( ) i 0.001192

    1

    2

    1.143

    Regresie Exponentiala [cu baza n>0, n rezolvata Matriceal ca Regresie Lineara

    f x m n( ) m nx

    ln f( ) ln m( ) x ln n( )= F a b x=

    y 2.4 2.8 4.5 7.9 13.5 20.8 30.7 43.1 53.1 77.2( ) w ln yT

    ln yT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    0.875

    1.03

    1.504

    2.067

    2.603

    3.035

    3.424

    3.764

    3.972

    4.346

    x 1 1.1 1.3 1.6 1.9 2.1 2.3 2.5 2.6 2.8( )

    A a b( )a

    b

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    10( )U 1 1 1 1 1 1 1 1 1 1( )

    xT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    1

    1.1

    1.3

    1.6

    1.9

    2.1

    2.3

    2.5

    2.6

    2.8

    XN 0 UT XN 1 xT XN

    0 1

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    1 1

    1 1.1

    1 1.3

    1 1.6

    1 1.9

    1 2.1

    1 2.3

    1 2.5

    1 2.6

    1 2.8

    XN A w= XNT

    XN A XNT

    w= XNT

    XN 1

    XNT

    XN A XNTXN 1

    XNT

    w= A XNT

    XN 1

    XNT

    w= XNT

    XN 1

    XNT

    w 1.049

    1.933

    1.04947 ln m( )= m e 1.04947( )

    m 0.35

    1.93306 ln n( )= n e1.93306

    n 6.911

    fm x( ) 0.35012( ) 6.91062( )x

    z xT

    z

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    1

    1.1

    1.3

    1.6

    1.9

    2.1

    2.3

    2.5

    2.6

    2.8

    fm z( )

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    2.42

    2.936

    4.321

    7.717

    13.782

    20.286

    29.861

    43.955

    53.329

    78.499

    yT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    2.4

    2.8

    4.5

    7.9

    13.5

    20.8

    30.7

    43.1

    53.1

    77.2

    yT

    fm z( )

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    -0.02

    -0.136

    0.179

    0.183

    -0.282

    0.514

    0.839

    -0.855

    -0.229

    -1.299

  • 7/25/2019 Regresii rezolvate ca Functii Lineare .pdf

    11/17

    11( )

    Se1

    100

    9

    i

    yT

    i fm z( )i

    Se 0.11 stdev yT

    fm z( ) 0.59 Stdev yT fm z( ) 0.622 i 0 9

    1 0 1 2 3 4 5 6 7 8 9 10 110

    10

    20

    30

    40

    50

    60

    70

    80

    0

    10

    20

    30

    40

    50

    60

    70

    80

    Grafic Erori

    fm z( )i y

    T i

    i i

    stdev Vi 1

    n0

    n 1

    i

    Vi mean Vi 2

    1

    2

    =

    Stdev Vi 1

    n 1( )0

    n 1

    i

    Vi mean Vi 2

    =

    1

    100

    9

    i

    yT

    i fm z( ) i 0.001192

    1

    2

    0.6

    1

    9 0

    9

    i

    yT

    i fm z( )i 0.001192

    1

    2

    0.633

  • 7/25/2019 Regresii rezolvate ca Functii Lineare .pdf

    12/17

    Regresie multilineara REZOLVATA CLASIC : Metoda Sumei celor mai mici patrate

    y(x1,x2,x3,x4) = a + bx1 + cx2 + dx3 + hx4 12( )

    Spatiul cu 5 dimensiuni :

    Fma b c d h x1 x2 x3 x4 a b x1 c x2 d x3 h x4 x3t 2.36 2.64 2.87 2.99 3.65 4.44 4.86 5.69 5.88 6.33( )

    x1t 1.11 1.25 1.49 1.61 1.82 2.05 2.27 2.44 2.61 2.89( ) x4t 1.51 1.96 2.31 2.45 2.84 3.14 3.59 4.75 5.02 5.66( )

    x2t 1.25 1.39 1.85 1.93 2.35 2.72 3.08 3.74 3.93 4.26( ) Yt 14.2 15.5 18.4 20.4 22.3 22.9 26.7 35.2 44.4 53.9( )

    x1tT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    1.11

    1.25

    1.49

    1.61

    1.82

    2.05

    2.27

    2.44

    2.61

    2.89

    x2tT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    1.25

    1.39

    1.85

    1.93

    2.35

    2.72

    3.08

    3.74

    3.93

    4.26

    x3tT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    2.36

    2.64

    2.87

    2.99

    3.65

    4.44

    4.86

    5.69

    5.88

    6.33

    x4tT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    1.51

    1.96

    2.31

    2.45

    2.84

    3.14

    3.59

    4.75

    5.02

    5.66

    Se defineste: U 1 1 1 1 1 1 1 1 1 1( ) Necunoscute a, b, c, d, h

    S a b c d h( )

    0

    n

    i

    Fi yi 2

    = n 5 Fi yi diferenta pentru fiecare punct= Fm xtT

    1 YtT

    1 Fm xtT

    2 YtT

    2 . . .

  • 7/25/2019 Regresii rezolvate ca Functii Lineare .pdf

    13/17

    13( )

    with :a

    Sd

    d0=

    bS

    d

    d0=

    cS

    d

    d0=

    dS

    d

    d0=

    hS

    d

    d0=

    S a b c d h( )

    0

    9

    j

    Fm xitT

    .j Yt T

    j

    2

    =

    a, b, c, d, h

    |

    |

    |

    |

    |

    |

    |

    |

    |

    |

    |

    |

    |

    |

    aS

    d

    d0=

    bS

    d

    d0=

    cS

    d

    d0= 2( ) Sistem de 5 ecuatii cu 5 necunoscute

    dS

    d

    d0=

    hS

    d

    d0=

    S a b c d h( )

    0

    9

    i

    a b x1tT

    i c x2t

    T

    i

    d x3tT

    i

    h x4tT

    i

    YtT

    i

    2

    U 0 1 2 3 4 5 6 7 8 9

    0 1 1 1 1 1 1 1 1 1 1

    aS

    d

    d2

    0

    9

    i

    a b x1tT

    i c x2t

    T

    i

    d x3tT

    i

    h x4tT

    i

    YtT

    i

    = 0=

    0

    9

    i

    YtT

    i

    U YtT

    = v0 U Yt T

    bS

    d

    d2

    0

    9

    i

    a b x1tT

    i c x2t

    T

    i

    d x3tT

    i

    h x4tT

    i

    YtT

    i

    x1tT

    i

    = 0=

    0

    9

    i

    YtT

    i x1t

    T

    i

    Yt x1tT

    = v1 Yt x1tT

  • 7/25/2019 Regresii rezolvate ca Functii Lineare .pdf

    14/17

    14( )

    cS

    d

    d2

    0

    9

    i

    a b x1tT

    i c x2t

    T

    i

    d x3tT

    i

    h x4tT

    i

    YtT

    i

    x2tT

    i

    = 0=

    0

    9

    i

    YtT

    i x2t

    T

    i

    Yt x2tT

    = v2 Yt x2tT

    dS

    d

    d2

    0

    9

    i

    a b x1tT

    i c x2t

    T

    i

    d x3tT

    i

    h x4tT

    i

    YtT

    i

    x3tT

    i

    = 0=

    0

    9

    i

    YtT

    i x3t

    T

    i

    Yt x3tT

    = v3 Yt x3tT

    hS

    d

    d2

    0

    9

    i

    a b x1tT

    i c x2t

    T

    i

    d x3tT

    i

    h x4tT

    i

    YtT

    i

    x4tT

    i

    = 0=

    0

    9

    i

    YtT

    i x4t

    T

    i

    Yt x4tT

    = v4 Yt x4tT

    0

    9

    i

    1

    10

    0

    9

    i

    x1tT

    i

    U xtT

    =

    0

    9

    i

    x2tT

    i

    U x2tT

    =

    Definesc : Elementele matricei M[5 x 5]

    M1 10 M2 U x1tT

    M3 U x2tT

    M4 U x3tT

    M5 U x4tT

    M2 U x1tT

    N1 x1tx1tT

    N2 x1t x2t

    T N3 x1t x3t

    T N4 x1t x4t

    T

    M3 U x2tT

    N2 x1tx2tT

    P1 x2t x2tT

    P2 x3tx2tT

    P3 x4t x2tT

    M4 U x3tT

    P2 x2t x3tT

    Q1 x3t x3tT

    Q2 x4t x3tT

    N3 x1t x3t

    T

    Q2 x3t x4tT

    R1 x4t x4tT

    M5 U x4t

    T N4 x1t x4t

    T P3 x2t x4t

    T

  • 7/25/2019 Regresii rezolvate ca Functii Lineare .pdf

    15/17

    15( )

    M

    M1

    M2

    M3

    M4

    M5

    M2

    N1

    N2

    N3

    N4

    M3

    N2

    P1

    P2

    P3

    M4

    N3

    P2

    Q1

    Q2

    M5

    N4

    P3

    Q2

    R1

    M

    10

    19.54

    26.5

    41.71

    33.23

    19.54

    41.392

    57.528

    89.311

    72.317

    26.5

    57.528

    80.629

    124.678

    101.491

    41.71

    89.311

    124.678

    193.391

    156.821

    33.23

    72.317

    101.491

    156.821

    128.072

    V1

    v0

    v1

    v2

    v3

    v4

    V1

    273.9

    601.08

    845.39

    1.304 103

    1.071 103

    M 0.192 M 1

    10.205

    15.201

    15.671

    3.796

    1.834

    15.201

    30.073

    22.887

    1.39

    3.399

    15.671

    22.887

    36.151

    9.657

    7.966

    3.796

    1.39

    9.657

    5.647

    0.939

    1.834

    3.399

    7.966

    0.939

    3.727

    Fma b c d h x1 x2 x3 x4 a b x1 c x2 d x3 h x4

    M 1

    V1

    6.594

    13.995

    19.901

    2.283

    20.733

    a 6.594

    b 13.995

    c 19.901

    d 2.283

    h 20.733

    Se por compara

    rezultatele obtinute

    prin cele doua

    metode.

    Fs x1t x2t x3t x4t 6.594 13.995x1t 19.901 x2t 2.283 x3t 20.733 x4t

    Fs x1tT

    x2tT

    x3tT

    x4tT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    9.983

    17.847

    18.783

    21.499

    22.658

    22.93

    27.216

    38.616

    42.378

    51.971

    YtT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    14.2

    15.5

    18.4

    20.4

    22.3

    22.9

    26.7

    35.2

    44.4

    53.9

    Fs x1tT

    x2tT

    x3tT

    x4tT

    YtT

    0

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    -4.217

    2.347

    0.383

    1.099

    0.358

    0.03

    0.516

    3.416

    -2.022

    -1.929

  • 7/25/2019 Regresii rezolvate ca Functii Lineare .pdf

    16/17

    16( )Calculul erorilor m

    0

    9

    i

    Fs x1tT

    x2tT

    x3tT

    x4tT

    i YtT

    i

    10

    m 2.054 10 3

    0 1 2 3 4 5 6 7 8 9 10

    12

    24

    36

    48

    60

    12

    24

    36

    48

    60

    Fs x1tT

    x2tT x3t

    T x4tT i Yt

    T i

    i i

    Invers : Fiind data o relatie liniara de forma ax+by+cz+... , relatie care descrie un fenomen oarecare,

    si fiind apoi posibil a se efectua masuratori asupra acestui fenomen,la momente diferite de timp : t1, t2, t3,..., rezulta in final, urmatoarele date notate (1), (2),...(6) si

    marcate cu culoare verde, astfel :

    Valorile notate 1,2...6 cu culoare verde,

    sunt valori masurate

    Valorile expresiilor algebrice

    pentru [xo ; yo] determinati :x 0.51 1.51 , Relatie necesara pentru afisarea graficului

    Sa se rezolve sistemul

    de ecuatii simultane:

    xo 1.03 yo 2.011Prelucrez sistemul de ecuatii dupa acelasi procedeu, si rezulta (xo, yo)

    1( ) xo yo 3.041 e1 3 3.041 e1 0.0411( ) x y 3=

    2( ) 3 xo yo 1.079 e2 1 1.079 e2 0.0792( ) 3 x y 1=

    3( ) 2xo yo 4.071 e3 4.1 4.071 e3 0.0293( ) 2x y 4.1=

    A

    1

    3

    2

    3

    1

    1

    1

    1

    1

    1

    1

    3

    AT

    A 25

    5

    5

    14

    B

    3

    1

    4.1

    5.3

    1.2

    6.9

    4( ) 3xo yo 5.101 e4 5.3 5.101 e4 0.199

    4( ) 3x y 5.3=5( ) xo yo 0.981 e5 1.2 0.981 e5 0.219

    5( ) x y 1.2=6( ) xo 3yo 7.063 e6 6.9 7.063 e6 0.163

    6( ) x 3y 6.9=

  • 7/25/2019 Regresii rezolvate ca Functii Lineare .pdf

    17/17

    17( )

    AT

    A 1

    AT

    B 1.03

    2.011

    xo 1.03= yo 2.011=Media erorilor = Me :

    e1 e2 e3 e4 e5 e6

    60.019

    0.50 0.70 0.90 1.10 1.30 1.500.00

    0.50

    1.00

    1.50

    2.00

    2.50

    3.00

    3.50

    4.00

    2.011

    3 x

    1 3x

    4.1 2 x

    5.3 3x

    1.2 x

    2.3 0.33x

    1.03

    x

    Solutia ar trebui sa fie [1 ; 2]

    Fiecare ecuatie este aprox.egala

    cu valorile obtinute

    din inlocuirea : xp=1 ; yp=2.

    Rezultat real : xo=1.03 ; yo=2.011

    xo xp 3.0% xp=

    yo yp 1.1% yp=

    Me Mo 1.9%=

    eof

    =============================================================================================================================