Sisteme de numeraţie
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Sisteme de numeraţie
Transcript of Sisteme de numeraţie
1
Cursul 3 Bazele aritmetice ale calculatoarelor.
Anexa 2 INFORMATIC APLICATAnexa 2 INFORMATIC APLICAT
Sisteme de numeraieOperaii aritmetice cu numere fr semn
Adunarea
Exemple
1.
(
Explicaie: 0+1=1
1+1=10 (se scrie 0, transport 1)
(1+0)+1=10 (se scrie 0, transport 1)
(1+0)+0=1
1+1=102.
(
Explicaie: 1+1=10 (se scrie 0, transport 1)
(1+0)+1=10 (se scrie 0, transport 1)
(1+1)+1=10+1=11 (se scrie 1, transport 1)
(1+0)+0=1
(1+1)=10 (se scrie 0, transport 1)
(1+0)+0=1
0+0=0
0+1=1
3.
(
Explicaie: 0+1=1
1+0=1
1+1=10 (se scrie 0, transport 1)
(1+1)+1=10+1=11 (se scrie 1, transport 1)
(1+1)=0=10 (se scrie 0, transport 1)
(1+1)+0=10 (se scrie 0, transport 1)
(1+0)+0=1
1+1=10 (se scrie 0, transport 1)
4.
(
Explicaie: 0+1+0=1
0+1+0=1
1+1+0=10 (se scrie 0, transport 1)
(1+1)+0+1=10+1=11
5.
(
Explicaie: 1+1+0=10 (se scrie 0, transport 1)
(1+1)+0+1=10+1=11 (se scrie 1, transport 1)
(1+1)+0+1=10+1=11 (se scrie 1, transport 1)
(1+1)+1+0=10+1=11
6.
(
Explicaie: 1+0=1
1+1=10 (se scrie 0, transport 1)
(1+0)+1=10 (se scrie 0, transport 1)
(1+1)+0=10 (se scrie 0, transport 1)
(1+0)+1=10 (se scrie 0, transport 1)
(1+0)+0=1
(1+1)= 10 (se scrie 0, transport 1)
(1+0)+1=10
7.
(
Explicaie:A+B=10+11=16+5=1016+5 (se scrie 5, transport 1)
(1+1)+4=6
8.
(
Explicaie:F+E=15+14=16+13=1016+13 (se scrie D, transport 1)
(1+F)+1=(1+15)+1=16+1=1016+1=11
9.
(
Explicaie:
F+E+7=15+14+7=36=2(16+4=2(1016+4 (se scrie 4, transport 2)
(2+F)+1+4=17+5=1016+6=16 10.
(
Explicaie: 2+1=3
3+F=3+15=1(1016+2 (se scrie 2, transport 1)
(1+B)+D=12+13=25=1(1016+9 (se scrie 9, transport 1)
(1+6)+4=11=B11.
(
Explicaie:
2+4+1=7
A+9+F=10+9+15=2(1016+2 (se scrie 2, transport 2)
(2+8)+1+C=11+12=23=1(1016+7 (se scrie 7, transport 1)12.
(
Explicaie:
9+6 = 15 = F
B+E=11+14 = 25 = 1(1016+9 (se scrie 9, transport 1)
(1+9)+7=17=1(1016+1 (se scrie 1, transport 1)
(1+1)+C = 2+12=14 = E
Scderea
Exemple
1.
(
Explicaie:1 - 0 = 1
1 - 1 = 0
1 - 0 = 1
0 0 = 0
1-1 = 0
2.
(
Explicaie: 0-1 = 1 (se mprumut o unitate din stnga)
(1-1)-1 = 0-1 = 1(se mprumut o unitate din stnga)
(0-1)-1 = 1-1 = 0 (se mprumut o unitate din stnga)
(1-1)-0 = 0-0 = 0
3.
(
Explicaie: 0-1 = 1 (se mprumut o unitate din stnga)
(1-1)-1 = 0-1 = 1(se mprumut o unitate din stnga)
(1-1)-0 = 0
(0-1) = 1 (se mprumut o unitate din stnga)
(1-1)-0 = 0
0 0 = 0
1 1 = 0
1 - 0 = 1
4.
(
Explicaie: 1-1-0 = 0
1-1-0 = 0
(1-1)-1 = 0-1 = 1(se mprumut o unitate din stnga)
(1-1)-0-0 = 0-0-0 = 05.
(
Explicaie:0-1 = 1 (se mprumut o unitate din stnga)
(1-1)-1 = 0-1 = 1(se mprumut o unitate din stnga)
(1-0)-1 = 1-1 = 0
1-0 = 16.
(
Explicaie:1-1 = 0
1-1 = 0
0-1 = 1 (se mprumut o unitate din stnga)
(1-1)-1 = 0-1 = 1 (se mprumut o unitate din stnga)
(1-1)-0 = 0
7.
(
Explicaie:
A-C = (16+A)-C = E (se mprumut o unitate din stnga)
1-1 = 08.
(
Explicaie:
F-A = 5
E-F = (16+E)-F = 15 = F (se mprumut o unitate din stnga)
8-1-1 = 6
2-1 = 19.
(
Explicaie:
2-1 = 1
3-F = (16+3)-F = 4 (se mprumut o unitate din stnga)
(B-1)-D = (16+10)-13 = 13 = D (se mprumut o unitate din stnga)
(6-1)-4 = 110.
(
Explicaie:
2-B = (16+2)-B = 18-11 = 7 (se mprumut o unitate din stnga)
9-D = (16+9)-D = 25-13 = 12= C (se mprumut o unitate din stnga)11.
(
Explicaie:
C-A = 2
B-9 = 11-9 = 2
A-8 = 10-8 = 212.
(
Explicaie:
E-F = (16+14)-F = 30-15 = 15 = F (se mprumut o unitate din stnga)
(F-1)-8 = 14-8 = 6
F-C = 15-12 = 3
A-4 = 10-4 = 6nmulirea
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EMBED Equation.3
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