Energii neconvenctionale proiect

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Tema proiect I= 880 [w/mp] 1800 litri Cu schimbator de cald ƞ= 0.64 S1p= 2 mp 36 mp 18 18 panouri 20275.2 W 0.691774 [l/s] 4187 J/kgK 7 ⁰C G1panou= 0.03843188 [kg/h] 36 persoane 14.4 ap. 15 rezulta P+3 etaje cu 4 apart Consideram Hu etaj=3m si Hu subsol=3.5m PENTRU TABLOURI FARA DISTRIBUITOR/COLECTOR(Asezare Tip1) Nr. Tr. G [kg/h] L [m] v [m/s] R [Pa/m] d [mm] R*l [Pa] Σξ TUR 1 138.35 2.5 0.32 113 15 2.825 2.8 2 276.7 2.5 0.42 144 18 3.6 0.3 3 415.05 2.5 0.4 100 22 2.5 0.3 4 553.4 2.5 0.35 58 28 1.45 0.3 5 691.9 2.5 0.43 85 28 2.125 0.65 6 830.25 3.5 0.32 37 35 1.295 0.3 7 1660.5 2 0.42 48 42 0.96 0.3 8 2490.75 14 0.39 31 54 4.34 1.9 RETUR 1' 138.35 2.5 0.32 113 15 2.825 3.4 2' 276.7 2.5 0.42 144 18 3.6 0.6 3' 415.05 2.5 0.4 100 22 2.5 0.6 4' 553.4 2.5 0.35 58 28 1.45 0.6 5' 691.9 2.5 0.43 85 28 2.125 0.95 6' 830.25 3.5 0.32 37 35 1.295 0.95 7' 1660.5 2 0.42 48 42 0.96 0.6 8' 2490.75 20 0.39 31 54 6.2 1.55 Vapa= Sp=Vapa/50= Np=Sp/S1p= Φ=I*ƞ*Np*S1p= G=Φ/cp*Δt= unde cp= unde Δt=

description

proiect

Transcript of Energii neconvenctionale proiect

Page 1: Energii neconvenctionale proiect

Tema proiectI= 880 [w/mp]

1800 litri Cu schimbator de caldura+vas de acumulareƞ= 0.64

S1p= 2 mp36 mp

18 18 panouri20275.2 W

0.691774 [l/s] 4187 J/kgK7 ⁰C

G1panou= 0.03843188 [kg/h]

36 persoane14.4 ap. 15 rezulta P+3 etaje cu 4 apart

Consideram Hu etaj=3m si Hu subsol=3.5m

PENTRU TABLOURI FARA DISTRIBUITOR/COLECTOR(Asezare Tip1)

Nr. Tr. G [kg/h] L [m] v [m/s] R [Pa/m] d [mm] R*l [Pa] ΣξTUR

1 138.35 2.5 0.32 113 15 2.825 2.82 276.7 2.5 0.42 144 18 3.6 0.33 415.05 2.5 0.4 100 22 2.5 0.34 553.4 2.5 0.35 58 28 1.45 0.35 691.9 2.5 0.43 85 28 2.125 0.656 830.25 3.5 0.32 37 35 1.295 0.37 1660.5 2 0.42 48 42 0.96 0.38 2490.75 14 0.39 31 54 4.34 1.9

RETUR1' 138.35 2.5 0.32 113 15 2.825 3.42' 276.7 2.5 0.42 144 18 3.6 0.63' 415.05 2.5 0.4 100 22 2.5 0.64' 553.4 2.5 0.35 58 28 1.45 0.65' 691.9 2.5 0.43 85 28 2.125 0.956' 830.25 3.5 0.32 37 35 1.295 0.957' 1660.5 2 0.42 48 42 0.96 0.68' 2490.75 20 0.39 31 54 6.2 1.55

Vapa=

Sp=Vapa/50=Np=Sp/S1p=

Φ=I*ƞ*Np*S1p=G=Φ/cp*Δt= unde cp=

unde Δt=

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Pierderi de sarcina-TURNr tr Cot TTS TTI TDS TDI RI RR

1 0.7 0.6 0.52 0.33 0.34 0.35 0.35 0.36 0.37 0.38 1.4 0.5

Pierderi de sarcina-RETURNr tr Cot TTS TTI TDS TDI RI RR

1' 0.7 1.2 0.52' 0.63' 0.64' 0.65' 0.35 0.66' 0.67' 0.68' 1.05 0.5

V cond retur V cond tur0.0004417865 0.00044178650.0006361725 0.00063617250.0009503318 0.00095033180.0015393804 0.00153938040.0015393804 0.00153938040.0033673946 0.00336739460.0027708847 0.00277088470.0458044209 0.03206309460.0570497518 0.0433084255

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Cu schimbator de caldura+vas de acumulare

P.d.s pt un panou la un debit de 122.35 kg/h e de 400 Pa

l ech [m] l ech tot Z [Pa] R*l+Z [Pa] Σ(Rl+Z) [Pa]TUR

0.37 1.036 117.068 119.893 119.8930.57 0.171 24.624 28.224 148.1170.69 0.207 20.7 23.2 171.3170.92 0.276 16.008 17.458 188.775

1 0.65 55.25 57.375 246.151.41 0.423 15.651 16.946 263.0961.41 0.423 20.304 21.264 284.361.44 2.736 84.816 89.156 752.252

RETUR0.37 1.258 142.154 144.979 144.9790.57 0.342 49.248 52.848 52.8480.69 0.414 41.4 43.9 188.8790.92 0.552 32.016 33.466 86.3141.15 1.0925 92.8625 94.9875 283.8665

1 0.95 35.15 36.445 225.3241.41 0.846 40.608 41.568 127.8821.44 2.232 69.192 75.392 700.716

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Pierderi de sarcina-TURTTCS TTCI CI intrare panou iesire panou Σξ

1 2.80.30.30.3

0.650.30.31.9

Pierderi de sarcina-RETURTTCS TTCI CI intrare panou iesire panou Σξ

1 3.40.60.60.6

0.95

0.61.55

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PENTRU TABLOURI CU DISTRIBUITOR/COLECTOR(Asezare Tip2)

Nr. Tr. G [kg/h] L [m] v [m/s] R [Pa/m] d [mm] R*l [Pa]TUR

1 611.25 4.5 0.357 62 28 2792 1222.5 4 0.42 64 35 2563 1833.75 22.5 0.44 53 42 1192.5

RETUR4 611.25 4.5 0.357 62 28 2795 1222.5 4 0.42 64 35 2566 1833.75 29 0.44 53 42 1537

Pierderi de sarcina-TURNr tr Cot TTS TTI TDS TDI RI

1 0.7 0.6 0.52 0.33 1.05 0.5

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Pierderi de sarcina-RETURNr tr Cot TTS TTI TDS TDI RI

4 0.7 0.6 0.55 0.66 1.05 0.5

V cond retur0.00277088470.003848451

0.04017782840.0467971642

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PENTRU TABLOURI CU DISTRIBUITOR/COLECTOR(Asezare Tip2)

Σξ l ech [m] l ech tot Z [Pa] R*l+Z [Pa] Σ(Rl+Z) [Pa]TUR

2.8 1 2.8 173.6 452.6 452.60.3 1.41 0.423 27.072 283.072 735.672

1.55 1.44 2.232 118.296 1310.796 4046.468

RETUR2.8 1 2.8 173.6 452.6 2452.60.6 1.41 0.846 54.144 310.144 4762.744

1.55 1.44 2.232 118.296 1655.296 8418.04

Pierderi de sarcina-TURRR TTCS TTCI CI intrare panou iesire panou Σξ

1 2.80.3

1.55

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Pierderi de sarcina-RETURRR TTCS TTCI CI intrare panou iesire panou Σξ

1 2.80.6

1.55

Aleg Ferroli ECOTOP V5V cond tur

0.00277088470.003848451

0.03117245310.0377917888

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Pierderi de sarcina-RETURPANOU

200020002000

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Debit pompa = 1.83 [m3/h] Alegerea schimbatorului de calduraPierdere de sarcina= 10278.87 [Pa] Q=

1.03 [m] G=*pierdere SC = 88.259 mbar Alegem SC Z2/13 P cu o pierdere de sarcina de 8825.9 Pa

8825.9 PaAleg pompa WILO IP-E 32/110-0.75/2

Volum apa = 1800 [l]Aleg rezervor de acumulare ACZ 1500E

Calculul vasului de expansiune - asezarea 1

Vapa = np*Vp+Vsb+Vpmp+Vcond = 154.06 [l]np = 18 panouriVp = 1.55 [l]Vsc = 24.8 [l]Vpmp = 1 [l]Vcond = 100.36 [l]

ppr = 0.1*hst+0.4 = 1.55 [bar]hst = 11.5 [m]

pincarcare = ppr+0.3 = 1.85 [bar]

pe = 0.9*pmax = 9 [bar]pmax = ppanou = 10 [bar]

Vevap = np*Vp = 27.9 [l]

Vvex = (7.3/100*Vapa+Vevap)*(pe+1)/(pe-pincarcare) = 54.750 [l]

Calculul vasului de expansiune - asezarea 2

Vapa = nbp*Vbp+Vsb+Vpmp+Vcond = 133.639 [l]nbp = 3 blocuri panouriVbp = 7.75 [l]Vsc = 24.8 [l]Vpmp = 1 [l]Vcond = 84.59 [l]

ppr = 0.1*hst+0.4 = 1.7 [bar]hst = 13 [m]

pincarcare = ppr+0.3 = 2 [bar]

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pe = 0.9*pmax = 9 [bar]pmax = ppanou = 10 [bar]

Vevap = nbp*Vbp = 23.25 [l]

Vvex = (7.3/100*Vapa+Vevap)*(pe+1)/(pe-pincarcare) = 47.151 [l]

ALEGEM 2 VASE DE EXPANSIUNE DE LA CALORSERV ERE 50 ...pt fiecare asezare

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Alegerea schimbatorului de caldura20.2752 KW= 14617.36 kcal/h

0.000692 m3/hAlegem SC Z2/13 P cu o pierdere de sarcina de 8825.9 Pa

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