Proiectarea unui cuptor pentru procese de prelucrare a reziduurilor

Date de proiectare 1. Materia prim : pcur de distilat atmosferic2. Capacitatea de prelucrare: 100000 t/an3. Numrul de ore de funcionare: 8000 h/an4. Caracteristicile materiei prime: g/cm35. Factorul de caracterizare: = 10,756. Curba de distilare STAS: - tintrare = 320oC t30% STAS= ti+20oC t50%STAS= ti+69oC t70%STAS= ti+105oC t90%STAS= 485oC7. Temperatura intrare cuptor: 85oC8. Temperatura ieire convecie : 205oC9. Temperatura ieire radiaie: 600oC10. Raia de abur : %mas fa de mp:15% (abur suprancalzit 18 bar)11. Randament produse : %mas fa de mp:14%12. Distribuia produselor: Gaze :18 Benzin:16 Motorin:7 Reziduu: 5913. Caracteristici produse: Gaze: kg/kmol =0,86kcal/kgoC Benzin : kg/kmol Motorin : kg/kmol Reziduu: kg/kmol 14. Presiunea n cuptor la intrare: 16 bar 15. Flux termic n convecie: kcal/m2h16. Flux termic n radiaie: = 50000 kcal/m2h17. Caracteristicile serpentinei: L= 8 m =0,2 m dp=4 mm (grosimea perete)18. Cldura de reacie:

masa molar a mp Mp= masa molar medie a produselor +0,00806

Calcul1. Trasarea curbei VE a materiei prime la presiunea din cuptor (Metoda Edmister-Okamoto)Pi cuptor= 16 bar= 15,79 atmt i =320oCt30%STAS= 320+20=340OCt50%STAS= 389oCt70%STAS= 425OCt90%STAS=485OC% volumT, oC,oC,oCtVE,oC

03201010493660153,45,63220384387

10330399

30340396

50389428

70425448

90485486

100500490

f()= tc, Pc=0,889 tc=560 Pc=140 N/cm2

F(1/t+273)=logP Punctul focallog=1,2VE, la p=15,79 atmt0%VE=576 t 70%VE=58t 10%VE =577 t 90%VE=581t 30%VE=578 t 100%VE=582t 50%VE=579mp=0,9952* mp+0,00806Mp=Xgaze*Mgaze+ Xmot*Mmot+ Xbz*Mbz=38,21 kg/kmol

Partea a-II-a Compoziia elementar a combustibilului.C=0,75h=1-c=0,25 Se consider ardere complet: 1 kmol O2/kg comb kmol aer/kg comb kmol aer/kg combCO2=0,0625 kmol CO2/kg combn H2O= kmol H2O/kg combn N2= 0,79*=0,470 kmol N2/kg comb ComponentniXiMimi

CO20,06250,0951442,75

H2O0,1250,190182,25

N20,4700,71482813,16

Total0,65751-18,16

Cp=A+B*T+C*T2+D*T3

CO2N2H2O

A=4,8900*102A=10,5696*102A=18,8370*102

B=1,4651B=-0,19734B=-0,16744

C=-0,94565*10-3C=0,49484*10-3C=0,84417*10-3

D=2,3023*10-7D=-1,86875*10-7D=-2,69764*10-7

=51186,23 kj/kg =

C2H4C3H6C4H8

A=1,47331*102A=0,89166*102A=-0,42553*102

B=5,53541B=5,57061B=6,22765

C=-2,91178*10-3C=-2,74061*10-3C=-3,41877*10-3

D=6,06153*10-7D=5,17085*10-7D=7,36451*10-7

T= 600+273,15=873,15 KCpC2H4=3,16 KJ/kg= 0,756 kcal/kgCpC3H6=0,766 kcal/kg =3,21 Kj/kgCpC4H8=3,28 Kj/kg= 0,783 kcal/kg

=363798,75 kcal/h

=

= 874,6 Kj/kg= 208,93 kcal/kg (ti= 205)

Qardere comb==522,98 kg/h*12227,9 kcal/kg = 6394991,9 kcal/h

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