4_2_PAL
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Transcript of 4_2_PAL
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7/23/2019 4_2_PAL
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ModulatorModulator
nn
cuadraturcuadratur
(I)(I)
Sistemul PAL utilizeaz semnale diferende culoare comprimate:
EU = kB EB-Y = 0,494
EB-Y
EV = kR ER-Y = 0,877 ER-Y
MAPS
MAPS
Oscilator
EV
EU
EVcosSPt
cosSPt
sinSPt
EUsinSPt
EC
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ModulatorModulator
nn
cuadraturcuadratur
(II)(II)
EC = EVcosSPt + EUsinSPt
= |EC|sin(SPt + C)
EU
|EC|
EV
C
2V
2UC EEE +=
U
VC
E
Etg =
saturaia culorii nuana culorii
alb
albastrunegru
verderou
LUMINAN
SATURAIE
NUAN
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PrincipiulPrincipiul
PALPAL (Phase Alternation Line)(Phase Alternation Line)
U
ECV
C U
ECV
C UEC
V
C
EC(n,)
U
ECV
C+
EC(n,)
EC
U
V
C U
EC
*
V
-C U
EC
*
V
-C
EC*(n+1,)
U
V
C-
EC**(n+1,)
linie n
linie n+1
iniial emisie canal cu eroare
de faz
recepie
C+
EC(n,)
U
V
C-
EC**(n+1,)
~2EC
ntrziere
TH
ECEC
n+1
n
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ModelulModelul color standard:color standard: saturasaturaieie 75%75%
(I)(I)
n sistemul PAL se limiteaz saturaia
maxim a culorii la 75%
amplitudinea vrf la vrf a semnalului EC(EY+|EC|,EY-|EC|) este limitat la:
1 = nivelul de alb
- 0,25 = jumtate din amplitudinea impulsului
de sincronizare
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ModelulModelul color standard:color standard: saturasaturaieie 75%75%
(II)(II)
Exemplu: Saturaie 100 %
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ModelulModelul color standard:color standard: saturasaturaieie 75%75%
(II(IIII))
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ModelulModelul color standard:color standard: saturasaturaieie 75%75%
((VIVI))
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LiniaLinia TV PALTV PAL
0,7V
0,3V
1VVV
UVF
EY
SC
SH
EY+EC
EY-EC
1
1,001,000,88
0,75
0,690,43
0,320,06 0
-0,13
-0,25-0,25
00,090,22
0,310,44
0,530,66
EY nivelul de griEC QAM peste nivelul de griSC burst fSC
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SpectrulSpectrul PAL (PAL (ntrentreesereesere 3/4)3/4)
Y
EU
EV
CEU+EV EU+EV EU+EV
EU+EVEU+EVY Y YEV EV EV
(k-1)fH kfH (k+1)fH
(k-1)fH kfH (k+1)fH
fSC4,43MHz
fH/2fH/2
fH3/4fH
283fH
discretkfH
identickfH
PAL: TV=2TH kfH/2
identickfH/2
fSC=(283+3/4)fH
ntreesere
3/4
f
f
f
f
f
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CodorulCodorul PALPAL
matrice
de codare
R
G
B
ntrziere
V
U
MODV
MODU
1
2
180
90
OSCfSC
(8/1135) timer
impuls
cos SPt
sin SPt
K
St S
SVCC
P
EC
EYEY
EV
EU
2fH
FTJ
FTJ
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DecodorulDecodorul PALPAL
ER
EG
EB
ntrziere
DEMOD
matrice
180
90burst
4,43 MHz
2EVcos SCt
sin SCt
SVCCPAL
EYEY
EV
EUDEMODsepararecomponente
2EUsin SCt
cos SCt
FTB
4,43EC
90
270
Rejecie
FTJ
FTJ
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SeparareaSepararea componentelorcomponentelordede culoareculoare
(I)(I)
2*+1,3+2*,...
2*-1,3-2*,...
demodulatoarentrziereTH= 64s
1
2
amplificatorcu ieire nantifaz
1
1
2*
1
2*
3
2*
3
4*
3
4*
EC:1,2*,3,4*,...
-+
EC= EVcos SPt + EUsin SPt
EC*= -EVcos SCt + EUsin SCt
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SeparareaSepararea componentelorcomponentelordede culoareculoare
(II)(II)
1 EC+EC* =
= EVcosSCt + EUsinSCt - EVcosSCt + EUsinSCt =2EUsin SCt
2 EC*-EC == -EVcosSCt + EUsinSCt - EVcosSCt - EUsinSCt
= -2EVcos SCt
EC-EC* =
= EVcosSCt + EUsinSCt + EVcosSCt - EUsinSCt
= 2EVcos SCt