div class=trans-pagebuttonPage 1button div class=trans-image amp-img class=trans-thumb alt=Page 1: SOLUTII PARTEA I›iiDin teorema sinusului avem sin B 100 — = 2R sin B = — 6 m4A + m4B + m4C = ABBCsinÐ 6-5sin30 m 4B = 15 SUBIECTUL 1 30 de puncte 1 G+2 G-2 src=https:reader030fdocumentecomreader030viewer20220405125e616cc173246c56c004353ehtml5thumbnails1jpg width=142 height=106 layout=responsive amp-img divp1pdivdiv class=trans-pagebuttonPage 2button div class=trans-image amp-img class=trans-thumb alt=Page 2: SOLUTII PARTEA I›iiDin teorema sinusului avem sin B 100 — = 2R sin B = — 6 m4A + m4B + m4C = ABBCsinÐ 6-5sin30 m 4B = 15 SUBIECTUL 1 30 de puncte 1 G+2 G-2 src=https:reader030fdocumentecomreader030viewer20220405125e616cc173246c56c004353ehtml5thumbnails2jpg width=142 height=106 layout=responsive amp-img divp2pdivdiv class=trans-pagebuttonPage 3button div class=trans-image amp-img class=trans-thumb alt=Page 3: SOLUTII PARTEA I›iiDin teorema sinusului avem sin B 100 — = 2R sin B = — 6 m4A + m4B + m4C = ABBCsinÐ 6-5sin30 m 4B = 15 SUBIECTUL 1 30 de puncte 1 G+2 G-2 src=https:reader030fdocumentecomreader030viewer20220405125e616cc173246c56c004353ehtml5thumbnails3jpg width=142 height=106 layout=responsive amp-img divp3pdivdiv class=trans-pagebuttonPage 4button div class=trans-image amp-img class=trans-thumb alt=Page 4: SOLUTII PARTEA I›iiDin teorema sinusului avem sin B 100 — = 2R sin B = — 6 m4A + m4B + m4C = ABBCsinÐ 6-5sin30 m 4B = 15 SUBIECTUL 1 30 de puncte 1 G+2 G-2 src=https:reader030fdocumentecomreader030viewer20220405125e616cc173246c56c004353ehtml5thumbnails4jpg width=142 height=106 layout=responsive amp-img divp4pdivdiv class=trans-pagebuttonPage 5button div class=trans-image amp-img class=trans-thumb alt=Page 5: SOLUTII PARTEA I›iiDin teorema sinusului avem sin B 100 — = 2R sin B = — 6 m4A + m4B + m4C = ABBCsinÐ 6-5sin30 m 4B = 15 SUBIECTUL 1 30 de puncte 1 G+2 G-2...