Calcul Termic Motor Diesel

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    Calculul termic al motorului cu aprindere prin comprimare

    Puterea nominala Pn= 30 kW 40.8 CP

    Turatia nominal nn= 3800 rot/min

    Numarul de cilindri i= 3

    Parametrii initiali

    T0= 293 K temperatura initialap0= 1.02 10! N/m2 pre"iunea initiala

    p"= 1.# 10! N/m2 pre"iunea de "upraalimentare

    n"= 1.$ e%ponent politropic tur&o"u'lanta

    T"= 3!2.#$!89!!2 K temperatura aerului la ie"irea din "u'la

    T"=To(p"/p")((n"*1)/n")

    deltaTi= 40 K racirea aerului in intercooler

    Tac= 312.#$!89!!2 K temperatura aerului la intrarea in cilin

    Tac=T"*deltaTi

    Tr= 8!0 temperatura +a,elor re,iduale

    pr= 1.1 10! pre"iunea +a,elor re,iduale

    lam&da= 1.$! -12!...22! coe'icientul de e%ce" de aer

    ep"ilon= 1$ -14....23 raportul de comprimare

    Parametrii proce"ului de "cim&are a +a,elor

    e adopta

    pa= 1.! 10! pre"iunea la "'ar"itul admi"iei

    deltaT= 20 preincal,irea ame"tecului

    nup= 1.1 -10!...12 coe'icient de po"tumplere

    e determina prin calcule

    Coe'icientul +a,elor re,iduale

    ammar= (TacdeltaT)pr/Tr(ep"ilon5pa5nup*pr)= 0.01#

    Temperatura la "'ar"itul admi"iei

    Ta=(TacdeltaT+ammarTr)/(1ammar)= 340.810 K

    Coe'icientul de umplere

    6ta7=((paTac/p"Ta)5(ep"ilon/(ep"ilon*1))5(nup/(1ammar))= 0.99

    Parametrii proce"ului de comprimare

    e adopta n1= 1.39 -13#...14 coe'icient politropic de comprimare

    e determina

    Pre"iunea la "'ar"itul comprimarii

    pc=pa5ep"ilonn1= $#.98$ 10! N/m2

    Temperatura la "'ar"itul comprimarii

    Tc=Ta5ep"ilon(n1*1)= 1028.934 K

    Parametrii proce"ului de ardere

    K -$00*900

    N/m2-10!..12!

    N/m2

    K -10...2!

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    e adopta c= 0.8!$ k+ compo,itia motorinei

    = 0.133 k+ compo,itia motorinei

    o= 0.01 k+ compo,itia motorinei

    i= 418#8 k/k+

    kcal/k+

    k"i= 0.8 :0$!..09; coe' de utili,are a caldurii

    pi= 1.8 :13..2!; coe' de cre"tere a pre"iunii

    ?Am5pi)5Tc=(Cm>BA)5mu'5T,

    *24.288 10*4 T,2 *34.8## T, 92308.9#4 =0

    D6T= am a am a * ,=

    K -1800...2400

    N/m2

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    Temperatura la "'ar"itul de"tinderii

    T&=T,/delta(n2*1)= 13#1.830 K -900..1200

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    Parametrii principali ai motorului

    e adopta coe' de rotunEire a dia+ramei mur= 0.9! -094..098randamentul mecanic etam= 0.8!

    Pre"iunea medie a ciclului teoretic "e o&tine din

    pi?=pc/(ep"ilon*1)5-pi(ro*1)pi5ro/(n2*1)5(1*1/(delta(n2*1))*1/(n1*1)(1*1/delta(n1*1));=

    pi?= 1#.991 N/m2

    Pre"iunea medie indicata

    pi=mur5pi?= 1#.142 510! N/m2

    Aandamentul indicat al motorului

    etaF=A5pi515To/(po5eta>5i)=83145pi5lam&daminTo/poeta>i=

    etaF= 0.808 -029...04!

    Pre"iunea medie e'ecti>a

    pe=etm5pF 13.$21 N/m2

    Aandamentul e'ecti>

    6tae=etam5etaF= 0.#8$ -02!...04

    Con"umul "peci'ic e'ecti> de com&u"ti&il

    +e=3#000/etae5i= 0.12! -2$0...340 k+/kW 12!.191 +/kW

    Dimensiunile fundamentale ale motorului

    e adopta GF=/D= 1.1 -09#...13

    Capacitatea cilindrica nece"ara

    7=120000pn/pe5n5i= 0.230 litri

    e determina ale,aEul "i cur"a

    D=(47/pi5GF)(1/3)= 0.#43 dm #4.34! mm

    0.0#4 m

    =GF5D= 0.$08 dm $0.$$9 mm

    0.0$1 m7ite,a medie a pi"tonului

    Wm=n/30= 8.9#!

    Cilindreea totala

    7t=i57= 0.#90 litri

    Puterea litrica

    Pl=Pn/7t= 43.449 kW/l -13....19

    Dia+rama indicata

    7olumul la "'ar"itul admi"iei

    7a=75ep"ilon/(ep"ilon*1)= 0.24! dm3

    510!-$!...1!

    m/" -10..12

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    7olumul la "'ar"itul compre"iei

    7c=7a/ep"ilon= 0.014

    p%=pa(7a/7%)n1

    p%=p,(7,/7%)n2

    e adopta

    3! oAan" la D6 al'a"= 40 oAelei "i lun+im al'ae>= am&da&= 1/3# 0.2$8

    H"=/2-(1*co"(al'a"))lam&da"/4(1*co"(2al'a"))= 8.01$ mm

    pcB=-11!...12!pc=12pc= 92.384 510! N/m2

    He>=/2-(1*co"(al'ae>))lam&da"/4(1*co"(2al'ae>))= 10.310 mm

    pa?=1/2(pap&)= 3.8#3 510! N/m2

    7c?=PF()5D25H"/4= 0.041 dm3

    7&?=7a*PF()5D25He>/4= 0.192

    7,=ro7c= 0.018

    7&=rodelta7c= 0.24!

    Caracteristica externa

    Puterea e'ecti>a

    Pe%=Pn:an%/np&(n%/np)2*(n%/np)3;=

    Con"umul "peci'ic

    +e%=+ep:c*dn%/npk(n%/np)2;=

    Con"umul orar

    c%=Pe%5+e%510(*3)=

    omentul motor

    e%=351045Pe%/(pi5n)=

    Con"tante

    otor a & c d k

    i,ata 0.# 1.4 1.3! 1.3! 1

    camera de >arteE 0.$ 1.3 1.2 1.2 1

    un+i de a>an" la aprindere -20...40oA

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    n :r/min; Pe :kW; +e :+/kW; e :k+/; e :Nm;

    1000 8.##9 1!1.#!1 1.31! 144.489

    1200 10.#$8 14!.2!3 1.!!1 148.30!

    1400 12.$1$ 139.!48 1.$$! 1!1.392

    1#00 14.$#0 134.!3$ 1.98# 1!3.$!1

    1800 1#.$81 130.220 2.18! 1!!.380

    2000 18.$!4 12#.!9# 2.3$4 1!#.280

    2200 20.#!2 123.##! 2.!!4 1!#.4!1

    2400 22.449 121.428 2.$2# 1!!.8942#00 24.119 119.88! 2.891 1!4.#0$

    2800 2!.#3! 119.03# 3.0!2 1!2.!91

    3000 2#.9$2 118.880 3.20# 149.84$

    3200 28.104 119.41$ 3.3!# 14#.3$3

    3400 29.003 120.#48 3.499 142.1$1

    3#00 29.#44 122.!$3 3.#34 13$.239

    3800 30.000 12!.191 3.$!# 131.!$9

    4100 0.000 #00.000 1.12$ 0.000

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    nta

    ru

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    Cinematica mecani"mului &iela*mani>ela

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    1!0 0.0482! $0.38992 2.28891 1.$$#48 *40!#.1014$

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    250 *0.2#408 !1.83392 1.#8!!1 *11.9$#24 *3109.1$$43

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    !20 0.00000 0.00000 0.00000 0.00000 $1#0.$1434

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    cotit

    ea &ielei

    ima

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    D= 0.0#43 m p0= 102000 N/m2 lam&da= 0.2$8

    = 0.0$08 m pa= 1!0000 N/m2 n1= 1.390

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    120 0.0!#8 0.1990 1 !0000.000 10.!022 *3!80.3!$2 1!#.0842 38$1.111! 402$.19!$ 0.2429 998

    130 0.0#10 0.2128 1!0000.000 8.8#18 *38$2.!199 1!#.0842 418$.0002 4343.0844 0.2144 94#

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